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When at t = 0, a particle at (1, 0, 0) m...

When at t = 0, a particle at (1, 0, 0) moves towards (4, 4, 12) with a constant speed of 65 m/s. The position of the particle is measured in meters and time in sec. Assuming constant velocity, the x
co-ordinate of the particle at t = 2 sec is:

Text Solution

Verified by Experts

The correct Answer is:
31
`x=x_(i)+Deltax`
`Deltax=v_(x)Deltat" "(Deltat="2 sec")`
`v_(x)=(x_(f)-x_(i))/(|Deltat|) and |Deltat|=(sqrt((4-1)^(2)+4^(2)+12^(2)))/(65)=(1)/(5)sec`
`x=5xx3xx2+1=31`
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