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For an element, Cp = 23 + 0.01 T("JK"^(-...

For an element, `Cp = 23 + 0.01 T("JK"^(-1)"mol"^(-1))` . If temperature of 3 moles of that element is raised from 300 K to 1000 K at 1 atm pressure, the value of `DeltaH` will be ______ kJ.

Text Solution

Verified by Experts

The correct Answer is:
61.95
`DeltaH=n int_(T_(1))^(T_(2))CpdT`
So, `DeltaH=3int_(300)^(1000)(23+0.01T)dT=61950J" "rArr" 61.95kJ"`
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