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If line (x-2)/(3)=(y-4)/(4)=(z+2)/(1) i...

If line `(x-2)/(3)=(y-4)/(4)=(z+2)/(1)` is parallel to planes `mux+3y-2z+d=0` and `x-2lambda y+z=0`, then value of `lambda` and `mu` are

A

`mu=4, lambda=-(2)/(3)`

B

`mu=-6, lambda=-2`

C

`mu=(-10)/(3), lambda=(-1)/(2)`

D

`mu=(-10)/(3), lambda=(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`3xxmu+4xx3+1xx(-2)=0`
`3mu=2-12`
`mu=(-10)/(3) and3xx1+4xx(-2lambda)+1xx1=0`
`-8lambda=-4," "lambda=(1)/(2)`
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