(~(pvvq))vv(~p^^q) is logically equivale...

`(~(pvvq))vv(~p^^q)` is logically equivalent to

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The correct Answer is:

A

`~(p vv q) vv (~p ^^ q) -=(p ^^ ~q) vv(~p^^q)-= ~ p ^^(~ q vvq) -= ~p ^^ t-=~p`.

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