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f(x)=(x^2-1)|x^2-3x+2|+cos|x| is not dif...

`f(x)=(x^2-1)|x^2-3x+2|+cos|x|` is not differentiable at x=a, then `sum_(r=0)^(oo)1/(a^r)` is equal to

A

1

B

2

C

0

D

`oo`

Text Solution

Verified by Experts

The correct Answer is:
B

`becausecos|x|` is differentiable everywhere as cos(-x)=cosx
Also using wavy curve method
`(x^(2))|x^(2)-3x+2|={{:((x-a)^(2)(x+1)(x+2)),(AAx in(-oo","-1)cup(2","oo)),(-(x-1)^(2)(x+1)(x-2)),(AAx in(1,2)):}`
`therefore`Not diff. at x=2`therefore`a=2
Now `sum_(r=0)^(oo)(1)/(2^(r))=(1)/(1-(1)/(2))=2`.
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