If the distance between foci of a hyperb...

If the distance between foci of a hyperbola is twice the distance between its directrices, then the eccentricity of conjugate hyperbola is :

A

2

B

` sqrt 3 `

C

`sqrt2 `

D

` ( 3 ) /(2) `

Verified by Experts

The correct Answer is:

C

`2ae = 2 xx (2a)/(e) , e^(2) = 2 rArr " " e = sqrt(2)`
`because " " (1)/(e_(H)^(2)) + (1)/(e_(CH)^(2)) = 1 " " rArr " " e_(CH) = sqrt(2)`

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