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Let A (0,2 ) , B ( 3, 0 ) , C ( 6, 4 ) ...

Let `A (0,2 ) , B ( 3, 0 ) , C ( 6, 4 ) ` be the vertices of triangle and P is a point inside the triangle such that area of triangle APB, BPC and CPA are equal. Equation of circle circumscribing ` Delta APB ` is :

A

` x ^ 2 + y^ 2 - 2x - 3y = 0`

B

` x ^ 2 + y ^ 2 - 4x - 3y = 0 `

C

` x ^ 2 + y ^ 2 - 3x - 4y = 0`

D

` x ^ 2 + y^ 2 - 3x - 2y = 0`

Text Solution

Verified by Experts

The correct Answer is:
D

`Delta PAB = Delta PBC = DeltaPCA " " rArr " " P` is centorid .
`P(3,2)`
Also `Delta APB` is a night angle .
Cirumcirle `rArr " " (x-0)(x-3)+(y-2)(y-0) = 0`
`rArr " " x^(2) + y^(2) - 3x - 2y = 0`
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