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Prove that tan7 1^circ/2 = sqrt6 - sqrt3...

Prove that `tan7 1^circ/2 = sqrt6 - sqrt3 + sqrt2 - 2`.

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Given,
`=>tan (7 (1/2)) = (sin (7 (1/2))°)/ (cos (7 (1/2))°)`
Multiplying by, `2sin(7(1/2))`
we have ,
` [2 sin^2(7 (1/2))°]/ [2 sin( 7 (1/2))cos (7 (1/2))°]`
...
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