Using graph find the number of points where `g(x) ` is non differentiable. `f(x)= x-3 ; x<0,x2-3x+2 ;x>0 or x=0g(x)=f(|x|) +|f(x)|`

If f(x) = [[x^(3),|x| =1] , then number of points where f(x) is non-differentiable is

Let f(x)=sin x,g(x)={{max f(t),0 pi Then number of point in (0,oo) where f(x) is not differentiable is

In f (x)= [{:(cos x ^(3),, x lt 0), ( sin x ^(3) -|x ^(3)-1|,, x ge 0):} then find the number of points where g (x) =f (|x|) is non-differentiable.

In f (x)= [{:(cos x ^(2),, x lt 0), ( sin x ^(3) -|x ^(3)-1|,, x ge 0):} then find the number of points where g (x) =f (|x|) is non-differentiable.

Consider the function f defined as f(x)=||x|-1| forallxepsilonR and another function g(x) such that g(x)=fof(x) . Find the number of points where g(x) is non differentiable

Let f(x)=15-|x-10| and g(x)=f(f(x)) then g(x) is non differentiable

If f (x)= [{:( cos x ^(2),, x lt 0),( sin x ^(3) -|x ^(3)-1|,, x ge 0):} then find the number of points where f (x) =f )|x|) is non-difierentiable.

Let f(x) be defined in the interval [-2,2] such that f(x)={-1;-2<=x<=0} and f(x)={x-1;0