The distance between the circumcentre and orthocenter of a `DeltaABC` is `Rsqrt(1-lambda cos A. cosB.cosC)`, then `lambda=`

Find the distance between the circumcentre and the incentre of the DeltaABC.

Find the distance between the circumcentre and the incentre of the DeltaABC.

Find the distance between the circumcentre and the incentre of the DeltaABC.

A triangle are (6,0).(0, 6) and (6,6) . If distance between circumcentre and orthocenter and distance between circumcentre and centroid are lambda and u unit respectively, then (lambda, u) lies on:

A triangle are (6,0).(0,6) and (6,6). If distance between circumcentre and orthocenter and distance between circumcentre and centroid are lambda and u unit respectively,then (lambda,u) lies on:

If in a DeltaABC , cos A + 2 cosB+cosC= 2 , then a,b, c are in

If in a DeltaABC , cos A + 2 cosB+cosC= 2 , then a,b, c are in

If the line joining the circumcentre 'O' and the incentre I is parallel to BC, then cosB + cosC =

In DeltaABC , the joining the circumcentre and incenre is parallel to BC then the value of cos B+cosC=