If `t a nalpha=p/q` , where `alpha=6beta,alpha` being acute angle, prove that `1/2{pcos e c2beta-qsec2beta}=sqrt(p^2+q^2)`

Explanation

To prove that

\[ \frac{1}{2} \left( p \csc 2\beta - q \sec 2\beta \right) = \sqrt{p^2 + q^2} \]

given that \(\tan \alpha = \frac{p}{q}\) and \(\alpha = 6\beta\), we will follow these steps:

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