Let D be a point on the side BC of a `Delta ABC` such that `BD : DC=3:4` and `/_ADC=theta; /_BAD=30^@; /_DAC=45^@` then `7cot theta=`

D is a point on the side BC of a triangle ABC such that /_ADC= /_BAC . Show that CA^(2)= CB*CD .

D is a point on the side BC of a triangle ABC /_ADC=/_BAC Show that CA^(2)=CB.CD

Let O be the in-centre of a triangle ABC and D be a point on the side BC of Delta ABC , such that OD_|_BC If angle BOD=15^(@) , then angle ABC=?

A point D is on the side BC of an equilateral triangle ABC such that DC=(1)/(4)BC. Prove that AD^(2)=13CD^(2)

In the given figure , D is a point on the side BC of Delta ABC such that angle ADC=angle BAC . Prove that CA^(2)=CBxxCD .

D is a point on the side BC of triangle ABC such that angle ADC = angle BAC . If CA = 12 cm and BC = 16 cm, then the length of CD is :

In triangle ABC. Dis on AC such that AD = BC, BD = DC, angleDBC = 2theta angleBAD=3 theta then theta=