The radius of the circle `x^2 +y^2 +z^2 = 49, 2x + 3y-z-5sqrt(14) = 0 is`

The radius of the circle in which the sphere x^2+y^2+z^2+2x-2y-4z-19=0 is cut by the plane x+2y+2z+7=0 is

The radius of the circle in which the sphere x^2+y^2+z^2+2x-2y-4z-19=0 is cut by the plane x+2y+2z+7=0 is

If the equation of the sphere through the circle x ^(2) +y ^(2) + z ^(2) = 9, 2x + 3y + 4z = 5 and through the point (1,2,3) is 3 (x ^(2) + y ^(2) + z ^(2)) - 2x - 3y - 4z = C, then the value of C is

The centre and radius of the sphere 3x^(2) + 3y^(2) + 3z^(2) - 2x - 12y + 6z + 7 = 0 are

If the equation of the sphere through the circle and the plane x ^(2) + y ^(2) + z^(2) = 5, 2x + 3y + 4z = 5 and through the origin is x ^(2) + y ^(2) + z ^(2) - 2x - 3y - 4z + c =0 .Then value of c is

radius of circle x^(2)+y^(2)+z^(2)-2y-4z-20=0,x+2y+2z=15

The radius of the circle in which the sphere x^(2)+y^(2)+z^(2)+2x-2y-4z-19=0 is cut by the plane x+2y+2z+7=0 is