Find in degree the angle subtended at the centre of a circle of diameter `50c m` by an arc of length `11c m` .

Explanation

Here, `=25 ~cm` and `s=11 ~cm`. Therefore,



`theta=(frac{S}{r})^{ R} ` or



`theta=(frac{11}{25})^{ {R}}=(frac{11}{25} times frac{180}{pi})^{0}`



`=(frac{11}{25} times frac{180}{22} times 7)^{circ} `



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