Given a random variable that takes values `X = {0, 1, 2}` and has a probability distribution, `P(0)= (1)/(4),P(1) = (1)/(2), P(2) = (1)/(4)`. Then find the variance of X.

A random variable X takes values 0, 1, 2, 3,… with probability proportional to (x+1)((1)/(5))^x . P(Xge2) equals

A random variable X has the following probability distribution: [[X=x,0,1,2,3], [P(X=x),(1)/(8),(1)/(2),(1)/(4),k]]

If a random variable x takes values 0,1,2 and 3 and the probability distribution is given by P(x) = kx , then find k and hence find the expected value of the distribution.

A random variable x has its range {0,1,2} and the probabilities are given by P(x=0) =3k^(3), P(x=1) =4k-10k^(2) , P(x=2) =5k-1 where k is a constant then k=

If 16x^(2)-p=(4x-(1)/(3))(4x+(1)/(3)) then find the value of p

A random variable X has the follwing probability distribution: Find P( 0 lt X lt 4)

If a random variable "X" takes values ((-1)^(k)2^(k))/k, k=1,2,3,... with probabilities P(X=k)=(1)/(2^(k)) , then E(X)

Gien that X is discrete random variable which take the values, 0,1,2 and P(X=0)=(144)/(169),P(X=1)=(1)/(169) , then the value of P(X=2) is

If X follows Poisson distribution such that P (X = 1) = 0.4 and P (X = 2) = 0.2, Then find the value of m

If (2p)/(p^(2)-2p+1)=(1)/(4),p!=0, then the value of p+(1)/(p)