If `acos theta-b sin theta=c ,` show that `asin theta+b cos theta=+-sqrt(a^2+b^2-c^2dot)`

Explanation

To solve the equation \( A \cos \theta - B \sin \theta = C \) and show that \( A \sin \theta + B \cos \theta = \pm \sqrt{A^2 + B^2 - C^2} \), we can follow these steps:

### Step 1: Start with the given equation
We have:
\[ A \cos \theta - B \sin \theta = C \]

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