The electric field in a region of space is given as `bar(E)=(5xhat i-2hat j)` .Potential at point `x` =1 `y`=1 is `V_(1)` and potential at point `x` =2 `y`=3 is `V_(2)` .Then` V_(1)-V_(2)` is equal to

The electric field strenth vector is given by E= 2.5x hat I + 1.5y hat .The potential at point (2,2,1) is (considering potential at origin to be zero)

The electric potential at a point (x,y,z) is given by V=-s^(2)

Electric field in a region is given by E=(2hati+3hatj-4hatk)V//m . Find the potential difference between points (0, 0, 0) and (1,2,3) in this region.

In Region of Electric field Given by vec(E)=(Ax-B)hat(I) . Where A=20 unit and B=10 unit. If Electric potential at x=1m is v_(2) . Then v_(1)-v_(2) is equal to

The electric potential in aregion of space is given by V=(5x-7x^(2)y+8y^(2)+16yz-4z) volt. The y-component of the electric field at the point (2,4,-3) is

Electric potential in a region of space is given by V=(x^(2)+y^(2)+z^(2))V . What will be electric field intensity at a point P(-1m, 2m, -3m)?

The electrostatic potential V at any point (x, y, z) in space is given by V=4x^(2)

An electric field vec E=(25hat i+30hat j)NC^(-1) exists in a region of space.If the potential at the origin is taken to be zero then the potential at x =2 m y =2 m is :?

The electric field in a region of space has the components E_(y) = E_(z) =0 and E_(x)= (4.00 N//C)x^(2) . Point A is on the y axis at y = 3.00 m, and point B is on the x axis at x = 4.00 m. What is the potential difference V_(B) - V_(A) ?