Home
Class 12
MATHS
If the equation of the ellipse with foci...

If the equation of the ellipse with foci `(+-4, 0)` and length of latus rectum `(20)/(3)` is `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1` then `(1)/(2)|a^(2)-b^(2)|` is equal to

Promotional Banner

Similar Questions

Explore conceptually related problems

If the equation of the ellipse with foci (pm4 ,0) and length of latus rectum (20)/(3) is (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 then (1)/(2)|a^(2)-b^(2)| is equal to

The length of latus rectum AB of ellipse (x^(2))/4+(y^(2))/3=1 is :

For the ellipse 3x ^(2) + 4y ^(2) =12, the length of latus rectum is

Find the length of the latus -rectum of the ellipse : (x^(2))/(4) + (y^(2))/(9) = 1 .

Find the eccentricity and the length of the latus rectum of the ellipse (x^(2))/(4) + (y^(2))/(25) = 1 .

Find the coordinats of the foci, the vertice ,eccentricity and length of latus rectum of ellipse (x^(2))/(25) + (y^(2))/(100) = 1 .

Find the coordinats of the foci, the vertice ,eccentricity and length of latus rectum of ellipse (x^(2))/(100) + (y^(2))/(100) = 1 .

Find the length of latus-rectum for the following ellipse: (x^(2))/(16)+(y^(2))/(9)=1

Find the eccentricity and the length of the latus rectum of the ellipse (x^(2))/(49) + (y^(2))/(36) = 1 .

Length of latus -rectum of the hyperbola (x^(2))/(a^(2)) - (y^(2))/(b^(2)) = 1 is ................. .