If `a, b in R` and `ax^2 + bx +6 = 0,a!= 0` does not have two distinct real roots, then :

If ax^(2) + bx + 10 = 0 does not have two distinct real roots, then the least value of 5a + b, is

If ax^(2)-bx+5=0 does not have two distinct real roots.Then find the minimum of 5a+b

If c<0 and ax^(2)+bx+c=0 does not have any real roots,then

Statement-1: If a, b, c are distinct real numbers, then a((x-b)(x-c))/((a-b)(a-c))+b((x-c)(x-a))/((b-c)(b-a))+c((x-a)(x-b))/((c-a)(c-b))=x for each real x. Statement-2: If a, b, c in R such that ax^(2) + bx + c = 0 for three distinct real values of x, then a = b = c = 0 i.e. ax^(2) + bx + c = 0 for all x in R .

If ax^(2)+bx=6=0 does not have distinct real roots,then find the least value of 3a+b .

If ax^(2)+bx+6=0 does not have two distinct real roots, a in R and b in R , then the least value of 3a+b is

If the equation ax^(2)+bx+c=0 does not have 2 distinct real roots and a+c>b, then prove that f(x)>=0,AA x in R

If ax^(2)-bx+5=0 does not have two distinct real roots, then find the minimun value of 5a+b.