The equilibrium constant of the given reaction at 100 degree C is 49. If a one-litre flask containing one mole of A_(2) is connected to a two-litre flask containing one moles of B_(2) how many moles of AB will be formed at 373K ?

The equilibrium constant of the reaction A_(2)(g)+B_(2)(g)hArr2AB(g) at 100^(@)C is 50. If a one litre flask containing one mole of A_(2) is connected to a two litre flask containing two moles of B_(2) , how many moles of AB will be formed at 373 K ?

The equilibrium constant for the reaction A_(2)(g) +B_(2) hArr 2AB(g) at 373 K is 50. If one litre flask containing one mole of A_(2) is connected to a two flask containing two moles of B_(2) , how many moles of AB will be formed at 373 K?

The equilibrium constant of the reaction A_(2)(g)+B_(2)(g) hArr 2AB(g) at 100^(@)C is 50 . If a 1-L flask containing 1 mol of A_(2) is connected to a 2 L flask containing 2 mol of B_(2) , how many moles of AB will be formed at 373 K ?

The K_(c) for A_(2(g))+B_(2(g))hArr2AB_((g)) at 100^(@)C is 50 . If one litre flasks containing one mole of A_(2) is connected with a two litre flask containing 2 "mole" of B_(2) , how many mole of AB will be formed at 100 ^(@)C ?

The value of K_(c) for the reaction: A_(2)(g)+B_(2)(g) hArr 2AB(g) at 100^(@)C is 49 . If 1.0 L flask containing one mole of A_(2) is connected with a 2.0 L flask containing one mole of B_(2) , how many moles of AB will be formed at 100^(@)C ?

The equilibrium constant of the reaction A_(2)(g)+B_(2)(g)hArr 2AB(g) at 373 K is 50. If 1 L of flask containing 1 mole of A_(2)(g) is connected to 2L flask containing 2 moles B_(2)(g) at 100^(@)C , the amount of AB produced at equilibrium at 100^(@)C would be