`tan^(-1)2-tan^(-1)1=tan^(-1)((1)/(3))`

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)1+tan^(-1)2+tan^(-1)3=

Prove that: tan^(-1)(1)/(7)+tan^(-1)(1)/(13)=tan^(-1)(2)/(9)tan^(-1)+tan^(-1)(1)/(5)+tan^(-1)(1)/(8)=(pi)/(4)tan^(-1)(3)/(4)+tan^(-1)(3)/(5)-tan^(-1)(8)/(19)=(pi)/(4)tan^(-1)(1)/(5)+tan^(-1)(1)/(7)+tan^(-1)(1)/(3)+tan^(-1)(1)/(8)=(pi)/(4)cot^(-1)7+cot^(-1)8+cot^(-1)18=cot^(-1)(1)/(13)

(tan^(-1)2+tan^(-1)3)=?

general solution of sec theta=(tan^(-1)(1)+tan^(-1)(2)+tan^(-1)(3))/(tan^(-1)1+tan^(-1)((1)/(2))+tan^(-1)((1)/(3))) is theta=

general solution of sec theta=(tan^(-1)(1)+tan^(-1)(2)+tan^(-1)(3))/(tan^(-1)1+tan^(-1)((1)/(2))+tan^(-1)((1)/(3))) is theta=

If 3tan^(-1)(2-sqrt(3))-tan^(-1)(x)=tan^(-1)((1)/(3)) then x=

tan^(-1)(1/2)+tan^(-1)(1/3)=?

Prove that 3tan^(-1)((1)/(2+sqrt(3)))-tan^(-1)((1)/(2))=tan^(-1)((1)/(3))