Home
Class 11
MATHS
Shortest distance between circle ((8x) -...

Shortest distance between circle `((8x) -33)^(2)+64y^(2)=1` and parabola `4y^(2)= x` is (A) 4 (B) `(33)/(8)` (C)` (sqrt(65)-1)/8` (D) `1/8`

Promotional Banner

Similar Questions

Explore conceptually related problems

The shortest distance between the circles x ^(2) + y ^(2) =1 and (x-9)^(2) + (y-12)^(2) =4 is

Shortest distance between the centre of circle x^2+y^2-4x-16y+64=0 and parabola y^2=4x is:

The shortest distance between the line " 2x-3y+1=0 " and the parabola " y^(2)=4x " ,is

The shortest distance between curves y^(2) =8x " and "y^(2)=4(x-3) is

The shortest distance between the line yx=1 and the curve x=y^(2) is (A)(3sqrt(2))/(8) (B) (2sqrt(3))/(8) (C) (3sqrt(2))/(5) (D) (sqrt(3))/(4)

The shortest distance between the line x=y and the curve y^(2)=x-2 is (a) 2 (b) (7)/(8) (c) (7)/(4sqrt(2)) (d) (11)/(4sqrt(2))

Area enclosed by the parabola y^2=8x and the line y=2x is (A) 4/3 (B) 3/4 (C) 1/4 (D) 1/2

The area of the circle x^2+y^2=16 exterior to the parabola y^2=6x is (A) 4/3(4pi-sqrt(3)) (B) 4/3(4pi+sqrt(3)) (C) 4/3(8pi-sqrt(3)) (D) 4/3(8pi+sqrt(3))

The shortest distance between the parabola y^2 = 4x and the circle x^2 + y^2 + 6x - 12y + 20 = 0 is : (A) 0 (B) 1 (C) 4sqrt(2) -5 (D) 4sqrt(2) + 5