A transverse wave is passing through a light string shown in fig.The equation of wave is `y=A sin(wt-kx)` the area of cross-section of string `A` and density is `rho` the hanging mass is :

Standing Wave Equation||Transverse wave in a string

The linear density of a vibrating string is 10^(-4) kg//m . A transverse wave is propagating on the string, which is described by the equation y=0.02 sin (x+30t) , where x and y are in metres and time t in seconds. Then tension in the string is

A wave travels on a light string. The equation of the wave is Y = A sin (kx - omegat + 30^(@)) . It is relected from a heavy string tied to an end of the light string at x = 0 . If 64% of the incident energy is reflected the equation of the reflected wave is

A wave travels on a light string. The equation of the waves is y= A sin (kx - omegat + 30^@) . It is reflected from a heavy string tied to an end of the light string at x = 0. If 64% of the incident energy is reflected, then the equation of the reflected wave is

A travelling wave in a stretched string is described by the equation y = A sin (kx - omegat) the maximum particle velocity is

The linear density of a vibrating string is 1.3 xx 10^(-4) kg//m A transverse wave is propagating on the string and is described by the equation y= 0.021 sin (x + 30 t) where x and y are measured in meter and t t in second the tension in the string is :-

Transverse waves pass through the strings A and B attached to an object of mass m as shown. If mu is the linear density of each of the strings the velocity of the transverse waves produced in the strings A and B is

A transverse wave propagating on the string can be described by the equation y=2sin(10x+300t) where x and y are in metres and t in second.If the vibrating string has linear density of 0.6times10^(-3)g/cm ,then the tension in the string is