`"If the radical centre of "x^(2)+y^(2)-4x+2y+3=0" "x^(2)+y^(2)-x+4y+4=0"and "x^(2)+y^(2)+2gx+5y+7=0" is (-1 1) then g= (A) -3 (B) 3 (C) -3/2 (D) 3/2"`

The radical centre of x^(2)+y^(2)-2x-2y+1=0, x^(2)+y^(2)-4x+6y-2=0 and x^(2)+y^(2)+3x-2y+4=0 is

Circles x^(2)+y^(2)=4 and x^(2)+y^(2)-2x-4y+3=0

if the radical centre of the three circles x^(2)+y^(2)-2x-1=0 and x^(2)+y^(2)-3y=1 and 2x^(2)+2y^(2)-x-7y-2=0 is Q then Q_(x)+Q_(y) is

The radical centre of the circles x^(2)+y^(2)=9 , x^(2)+y^(2)-2x-2y-5=0 , x^(2)+y^(2)+4x+6y-19=0 is A) (0,0) (B) (1,1) (C) (2,2) (D) (3,3)

The radical centre of three circles : x^2 + y^2 + x + 2y + 3 = 0, x^2 + y^2 + 2x + 4y + 5 = 0 and x^2 + y^2 - 7x - 8y - 9 = 0 is : (A) (- 2/3, - 2/3) (B) (1/3, 1/3) (C) (1/4, 1/4) (D) (0, 0)

x^(2) - 1 = 0, y^(2) + 4y + 3 = 0

Equation of radical axis of the circles x^(2) + y^(2) - 3x - 4y + 5 = 0 and 2x^(2) + 2y^(2) - 10x - 12y + 12 = 0 is

The radical centre of circles represented by S_(1)-=x^(2)+y^(2)-7x-6y-4=0,S_(2)-=x^(2)+y^(2)+10x+6y-4=0

Find the equation of radical axis of the circles x^(2)+y^(2)-3x+5y-7=0 and 2x^(2)+2y^(2)-4x+8y-13=0 .