If `t a ntheta+sintheta=m` and `tantheta-sintheta=n ,` show `m^(2-)n^2=4sqrt(m ndot)`

Explanation

To prove that \( m^2 - n^2 = 4 \sqrt{mn} \) given the equations \( m = \tan \theta + \sin \theta \) and \( n = \tan \theta - \sin \theta \), we will follow these steps:

### Step 1: Write down the expressions for \( m \) and \( n \)
We have:
\[ m = \tan \theta + \sin \theta \]
\[
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