Two particles P and Q are moving with velocities of `(i+j)` and `(-i+3j)` respectively. At time `t=0`, P is at origin and Q is at a point with position vector `(2i+j)` .Then the shortest distance between P& Q is:

Two particles P and Q are moving with velocity of (hat(i)+hat(j)) and (-hat(i)+2hat(j)) respectively. At time t=0 , P is at origin and Q is at a point with positive vector (2hat(i)+hat(j)) . Then the shortest distance between P & Q is :-

P,Q and R are three points with position vector i+j,i-j and ai +bj+ck respectively.if P,Q,R are collinear then

P,Q and R are three points with position vector i + j , i - j and ai +bj +ck respectively. if P,Q,R are collinear then

The distance between a point P whose position vector is 5i+j+3k and the line r=(3i+7j+k)+t(j+k) is

1.Given the vector PQ=-6i4j and Q is the point (3,3), find the point P.

If the position vector of a point P with respect to the origin O is i+3j-2k and that of a point Q is 3i+j-2k, then what is the position vector of the bisector of the /_POQ?

The position vectors of two given points P and Q are 8i+3j and 2i−5j respectively, find the magnitude and direction of the vector PQ