`y=int(x+1)/(xy)dy`

Let y=y(x) , y(1)=1 and y(e)=e^(2) .Consider J=int(x+y)/(xy)dy , I=int(x+y)/(x^(2))dx J-I=g(x) and g(1)=1 then the value of g(e) is

Let y=y(x) , y(1)=1 and y(e)=e^(2) . Consider J=int(x+y)/(xy)dy , I=int(x+y)/(x^(2))dx , J-I=g(x) and g(1)=1 then the value of g(e)

Let y=y(x) y(1)=1 and y(e)=e^(2) . Consider J=int(x+y)/(xy)dy I=int(x+y)/(x^(2))dx, J-I=g(x) and g(1)=1 then the value of g(e) is

int(1+x)/(x^(2))dx+int(1-y)/(y^(2))dy

If f(x) =x + int_(0)^(1) (xy^(2)+x^(2)y)(f(y)) dy, "find" f(x) if x and y are independent.

Suppose g(x) satisfies g(x)=x+int_(0)^(1)(xy^(2)+yx^(2))g(y)dy , then g(x) is

If xy=e^(x-y) , prove that (dy)/(dx)=(y(x-1))/(x(y+1)) .

Solve the differential equation (dy)/(dx)+(1)/(x)y=xy^(2)

If x+y=tan^(-1)(xy), find (dy)/(dx)

If f(x)=x+int_(0)^(1)(xy^(2)+x^(2)y)f(y)dy where x and y are independent variable.Find f(x)