A surface has the area vector `vec A=(2hat i+3hat j)m^(2)` ? The flux of an electric field through it if the fields is `bar(E)=4hat i(V)/(m)` :

A surface has the area vector vec(A) = (2 hat(i) + 3 hat(j)) m^(2) . The flux of an electric field through it if the field is vec(E) = 4 hat(i) (V)/(m) :

If the vectors vec a=2hat i-3hat j and vec b=-6hat i+mhat j are collinear,find the value of m

Vectors vec A=hat i+hat j-2hat k and vec B=3hat i+3hat j-6hat k are

A proton travels through uniform magnetic and electric tric fields. The magnetic field is vec(B) = -3.25 hat(i) mT . At one instant the velocity of the proton is vec(v) = 2000 hat(j) m//s . At that instant and in unit-vector notation. What is the net force acting on the proton if the electric field is (a) 4.00 hat(k) V/m, (b) -4.00 hat(k) V/m, and (c) 4.00 hat(i) V/m ?

For what value of m the vector vec A=2hat i+3hat j-6hat k is perpendicular to vec B=3hat i-mhat j+6hat k

The electric field in a certain region of space is (5 hat(i) + 4 hat(j) - hat(k)) xx 10^(5) N//C . Calculate electric flux due to this field over an area of (2 hat(i) - hat(j)) xx 10^(-2) m^(2) .

Show that the vectors vec(a)=2hat(i)+3hat(j) and vec(b)=4hat(i)+6hat(j) are parallel.

Find out the electric flux through an area 10 m^(2) lying in XY plane due to a electric field vec(E)=2hat(i)-10 hat(j)+5hat(k) .