(ii)quad (3y-2)+i(7-2x)=0

Find x and y, if (3y - 2) +i(7-2x) = 0.

Find x and y if: (3y-2)+i(7-2x)=0

Find x and y if: (3y-2)+i(7-2x)=0

A point which lies between 2x+3y-7=0 and 2x+3y+12-0 is (i)(5,1)( (ii) (-1,3)( iii) (-3,-5)( iv )(7,-1)

Find the values of x and y from the following : (i) (3x -7)+2iy=-5y+(5+ x)i (ii) 2x i+12= 3y-6i (iii) z=x+iy and i(z+2)+1=0 (iv) ((1+i)x-2i)/(3+i)+((2-3i)y+i)/(3-i)=i (v) (3x-2iy)(2+i)^(2)=10(1+i)

Find the values of x and y from the following : (i) (3x -7)+2iy=-5y+(5+ x)i (ii) 2x i+12= 3y-6i (iii) z=x+iy and i(z+2)+1=0 (iv) ((1+i)x-2i)/(3+i)+((2-3i)y+i)/(3-i)=i (v) (3x-2iy)(2+i)^(2)=10(1+i)

(i) x^(2) - 4x + 3 = 0 (ii) y^(2) - 7y+10 = 0

If (3+i)x + (1-2i)y + 7i = 0 , then the values of x and y respectively are