`tan^(2)theta-sin^(2)theta=sin^(4)theta sec^(2)theta`

(sec^(2)theta-sin^(2)theta)/(tan^(2)theta)=cosec^(2)theta-cos^(2)theta

sec^(2)theta-(sin^(2)theta-2sin^(4)theta)/(2cos^(4)theta-cos^(2)theta)=1

Value of sec^(2)theta-(sin^(2)theta-2sin^(4)theta)/(2cos^(4)theta-cos^(2)theta) is

Prove that sin theta sec3 theta=(1)/(2)[tan3 theta-tan theta] and hence find the sum to n terms of the series sin theta sec3 theta+sin3 theta sec3^(2)theta+sin3^(2)theta sec3^(3)theta+...

If sec^(4)theta+sec^(2)theta=10+tan^(4)theta+tan^(2)theta, then sin^(2)theta=(2)/(3)(b)(3)/(4)(c)(4)/(5)(d)(5)/(6)

Cosider the following : 1. tan ^(2) theta - sin ^(2) theta = tan ^(2) theta sin ^(2) theta 2. (cosec theta - sin theta ) (sec theta - cos theta ) (tan theta + cot theta ) =1 Which of the above is/are correct ?

Prove that (sin^(2)theta+cos^(2)theta)/(sec^(2)theta-tan^(2)theta)=1

Prove that (sec^2theta-sin^2theta)/tan^2theta=cosec^2theta-cos^2theta .

sec^(4)theta(1-sin^(4)theta)-2tan^(2)theta=1