If `log_3 2+log_3 (2^x-7/2)=2log_3 (2^x-5)` then `x=`

If log_3 2, log_3 (2^x -5) and log_3 (2^x-7/2) are in A.P , determine the value of x .

If log_(2)(3^(2x-2)+7)=2+log_(2)(3^(x-1)+1) then x=

The value of x for which the numbers log_3 2, log_3(2^x-5) and log_3(2^x- 7/2) are in A.P.=

If (log)_3 2,(log)_3(2^x-5) and (log)_3(2^x-7/2) are in arithmetic progression, determine the value of xdot

log_3 2 ,log_3(2^x-5) , log_3(2^x-7/2) are in A.P. then the value of x =?

If log_(3)2,log_(3)(2^(x)-5),log_(3)(2^(x)-7/2) are in arithmetic progression, then the value of x is equal to

If log_(3) 2, log_(3) ( 2^(x) - 5) and log_(3) ( 2^(x) - ( 7)/( 2)) are in A.P., then x is equal to :

If log_(3)2,log_(3)(2^(x)-5) and log_(3)(2^(x)-7/2) are in A.P., then x is equal to