Which of the following statemetnt is incorrect regarding Ellingham diagram for a metal ?

Options

A. In general, on increasing temperature free energy change also increses
B. Graph for which `DeltaS` is negative, will have positive slope
C. Graph for which `DeltaS` is negative, will have negative slope
D. None of these

Answer

C

Explanation

`(del(DeltaG))/(delT)=-DeltaS`

` therefore DeltaS lt 0,"Slope will be positive"`.