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Acl(2)(excess)+BCl(2) to Acl(4)+Bdownarr...

`Acl_(2)(excess)+BCl_(2) to Acl_(4)+Bdownarrow`
`BO underset(gt400^(@)C)overset(Delta)to(1)/(2)O_(2)+B_(2)`. If A and B metal then ore of B would be:

A

siderite

B

cinnabar

C

malachite

D

horn silver

Text Solution

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The correct Answer is:
B
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