[" 34."(999)^(2)-(998)^(2)=?],[[" (a) "1," (b) "999]]

((999)^(3)-1)/((999)^(2)-1)=?

(999)^(2)-(998)^(2)=?1992(b)1995(c)1997 (d) 1998

(i) quad (998)^(3)

Solve ((999+588)^(2)-(999-588)^(2))/(999xx588)

(999(999)/(1000)xx7)

((998)^(2) - (997)^(2) - 45)/((98)^(2) - (97)^(2)) equals

(2.0001)^(3)xx(1.999)^(-2)div(3.999)^(-4)=?

The value of 998(2)/(17)+998(3)/(17)+998(5)/(17)+998(8)/(17)+998(16)/(17) is (a) 4990( b) 4992(c)9998(d)10000