sec(x;(3x+5)(2x+7)=4

Solve: (3x+5)/(2x+7)=4

Solve: (3x+5)/(2x+7)=4

Solve the following equations : (3x+5)/(2x+7)=4

Find The horizontal asymptote of ((2x-3)^2(5x-4))/(x(3x-5)(7x-3))

Let cos(pi)/(7),cos(3 pi)/(7),cos(5 pi)/(7) are the roots of equation 8x^(3)-4x^(2)-4x+1=0 Q.The value of sec((pi)/(7))+sec((3 pi)/(7))+sec((5 pi)/(7)) is

If int (dx)/((2x-7) sqrt((x-3) (x-4))) = 1/k sec^(-1) (2x-7)+ c , then the value of k is -

lim_(x rarr0)(sec4x-sec2x)/(sec3x-sec x)=

Solve for x: 11^(4x-5)*3^(2x)=5^(3-x) * 7^(-x) .

Solve for x: 11^(4x-5)*3^(2x)=5^(3-x) * 7^(-x) .