[" Expless "],[1-cos theta+2i sin theta]" in "a+ib" form "

Express (1)/(1-cos theta+2i sin theta) in the form x+iy.

Express (1)/(1-cos theta+2i sin theta) in the form of a+ib .

Express (1)/(1+cos theta-i sin theta) in the form of a+ib.

Express 1/(1+cos theta-i sin theta) in the form of a +ib .

[(1 + cos theta + i sin theta) / (sin theta + i (1 + cos theta))] ^ (4) = cos n theta + i sin n theta

We express ((cos 2theta -i sin 2theta)^(4) (cos 4theta + i sin 4 theta)^(-5))/((cos 3theta + i sin 3theta)^(-2) (cos 3theta -i sin 3theta)^(-9)) in the form of x+iy , we get

If ((1 + cos theta + i sin theta ) /(i+ sin theta + i cos theta ))= cos ntheta + i sin n theta then n is equal to :

The mod-amp form of 1+cos theta+i sin theta is