A man standing on a hill top projects a stone horizontally with speed `v_0` as shown in figure. Taking the co-ordinate system as given in the figure. Find the co-ordinates of the point where the stone will hit the hill surface.

Explanation

Range of the projectile on an inclined (down the plane) is,
`R=(u^(2))/(g cos^(2)beta)[sin(2x+beta)+sin beta]`
Here, `u=v_(0),alpha=0,` and `beta=0`
`therefore R=(2v_(0)^(2)sin theta)/(g cos^(2)theta)`
Now, `x=R cos theta=(2v_(0)^(2)tan theta)/(g)`
and `y=-R sin theta=(2v_(0)^(2)tan^(2)theta)/(g)`