If the radius of earth is 6400km, calcu late (a) angu lar velocity (b) linear velocity and (c) radial accelration for a point on its equator considering its spin motion alone. What will be the values of above quantities if the pint is at the pole?

Explanation

As earth makes one rotation on its axis every 24hrs-
(a) `omega_(s)=(2pi//T)=(2pi//24xx60xx60)=7.3xx10^(-5)` rad/s
(b) `v=4omega=(6.4xx10^(6))(7.3xx10^(-5))=4.7xx10^(2)m//sapprox0.5` km/s
(c) `a_(r)=romega^(2)=(6.4xx10^(6))(7.3xx10^(-5))^(2)=3.4xx10^(-2)m//s^(2)`
Now, if the point is at pole, `r rarr0` so `v=(romega)` and `a_(r)(=romega^(2))`
will become zero while `omega` (chracteristic of rigid body ) will remain unchanged.