Two bodies P and Q are projected with velocites `sqrt(2)` u and u respectively. They cover the same horizontal distance. If body P is projected at `15^(@)` will the horizontal, then calcu late the angle of projection of body Q.

Answer

`45^(@)`

Explanation

`R_(P)=R_(Q)rArr((sqrt(2)u)^(2)sin(2xx15^(@)))/(g)=(u^(2)sin 2theta)/(g)`
`1=sin 2theta`
`theta=45^(@)`