It was calculated that a shell when fired from a gun with a certain velocity and at an angle of elevation `5pi//36` radius should strike a given target. In actual practice it was found that a hill just intervened in the trajectory. At what angle of elevation should the gun be fired to hit the target ?

Options

A. `(5pi)/(36)` radian
B. `(7pi)/(36)` radian
C. `(11pi)/(36)` radian
D. `(13pi)/(36)` radian

Answer

d

Explanation

To hit the same target the projectile can be fixed at complimentary angle i.e., `(pi)/(2)-(5pi)/(36)=(13pi)/(36)`