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A particle is projected at an angle of 4...

A particle is projected at an angle of `45^(@)` with a velocity of `9.8 ms^(-1)`. The horizontal range will be (Take, `g = 9.8 ms^(-2))`

A

9.8m

B

4.9m

C

9.8/ `sqrt(2)m`

D

`9.8sqrt(2)m`

Text Solution

Verified by Experts

The correct Answer is:
a
`R=(u^(2)sin2theta)/(g)`
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