a projectile is fired from the surface of the earth with a velocity of `5ms^(-1)` and angle `theta` with the horizontal. Another projectile fired from another planet with a velocity of `3ms^(-1)` at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth.The value of the acceleration due to gravity on the planet is in `ms^(-2)` is given `(g=9.8 ms^(-2))`

Options

A. `5.9m//s^(2)`
B. `3.5m//s^(2)`
C. `16.3m//s^(2)`
D. `8.5m//s^(2)`

Answer

b

Explanation

For identical trajectories
`(g)/(u^(2))=(g')/(u'^(2))`