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A particle is projected upwards with a velocity of `100 m//s` at an angle of `60^(@)` with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking `g = 10 m//s^(2)`.

A

10second

B

20second

C

5 second

D

10 `sqrt(3)` second

Text Solution

Verified by Experts

The correct Answer is:
b
`T=(u cosec theta)/(g)`
where `theta` is the angle made by initial velocity vector from horizontal.
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