The displacement of the point of a wheel initially in contact with the ground when the wheel rolls forward quarter revolution where perimeter of the wheel is `4pi m`, is (Assume the forward direction as x-axis)

Options

A. `sqrt((pi+2)^(@)+4)"along" tan^(-1)(2)/(pi)` with x-axis
B. `sqrt((pi-2)^(2)+4) "along" tan^(-1)(2)/(pi-2)` with x-axis
C. `sqrt((pi-2)^(2)+4)` along `tan^(-1)(2)/(pi)` with x-axis
D. `sqrt((pi+2)^(2)+4)` along `tan^(-1)(2)/(pi-2)` with x-axis

Answer

b

Explanation

`S=sqrt(y^(2)+x^(2))` and `theta=tan^(-1)((y)/(x))`