A cyclist is riding with a speed of `27 km h^(-1)`. As he approaches a circular turn on the road of radius 80 m, he applies brakes and reduces his speed at the constant rate `0.5 ms^(-1)`. What is the magnitude and direction of the net acceleration of the cyclist on the circular turn ?

Options

A. `0.5m//s^(2)`
B. `0.8m//s^(2)`
C. `0.56m//s^(2)`
D. `1 m//s^(2)`

Answer

c

Explanation

`a=sqrt(a_(c)^(2)+a_(r)^(2))`