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At a given instant of time the position ...

At a given instant of time the position vector of a particle moving in a circle with a velocity `3hati-4hatj+5hatk is hati+9hatj-8hatk`.Its anglular velocity at that time is:

A

`((13hati-29hatj-31hatk))/(sqrt(146)`

B

`((13hati-29hatj-31hatk))/(146)`

C

`((13hati+29hatj-31hatk))/(sqrt(146))`

D

`((13hati+29hatj+31hatk))/(146)`

Text Solution

Verified by Experts

The correct Answer is:
b
`vecomega=(vecrxxvecv)/(|vecr|^(2))`
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