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A particle when fired at an angle theta=...

A particle when fired at an angle `theta=60^(@)` along the direction of the breadth of a rectangular building of dimension `9mxx8mxx4m` so as to sweep the edges.Find the range of the projectile.

A

`8sqrt(3)`

B

`4sqrt(3)`

C

`(8)/sqrt(3)`

D

`(4)/sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
a

`y=h=x tan theta-(gx^(2))/(2u^(2)cos^(2)theta)`
`R=x+x+2hrArrx=(R)/(2)-h` and `R=(u^(2)sin 2 theta)/(g)`
using the above equations
`h=((R)/(2)-h)tan theta-(1)/(R)((R)/(2)-h)^(2)tan theta`
`rArr R=2h cot ((theta)/(@))`
putting `theta=60^(@),h=4m` then R=`8sqrt(3)m`
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