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Two bodies are projected from the same point with same speed in the directions making an angle `alpha_(1)` and `alpha_(2)` with the horizontal and strike at same point in the horizontal plane through a point of projection. If `t_(1)` and `t_(2)` are their time of flights.Then `(t_(1)^(2)-t_(2)^(2))/(t_(1)^(2)+t_(2)^(2))`

A

`(tan (alpha_(1)-alpha_(2))/(tan (alpha_(1)+alpha_(2)))`

B

`(sin (alpha_(1)+alpha_(2)))/(sin(alpha_(1)-alpha_(2)))`

C

`(sin(alpha_(1)-alpha_(2)))/(sin(alpha_(1)+alpha_(2)))`

D

`(sin^(2)(alpha_(1)-alpha_(2)))/(sin^(2)(alpha_(1)+alpha_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
c

`alpha_(1)+alpha_(2)=90^(@)`
`rArrsin(alpha_(1)+alpha_(2))=1`
`r_(a)=(2usin alpha_(1))/(g). T_(2)=(2u sin alpha_(2))/(g)`
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