A particle moves on a circle of radius r with centripetal accelration as function of time as `a_(c)=K^(2)rt^(2)` where k is a positive constant , find the resu ltant acceleration.

Options

A. `kt^(2)`
B. `kr`
C. `krsqrt(k^(2)t^(4)+1)`
D. `krsqrt(k^(2)t^(2)-1)`

Answer

c

Explanation

From given equation
`omega=kt`
`alpha=(domega)/(dt)=k, alpha_(t)=ralpha, alpha=sqrt(a_(c)^(2)+a_(r)^(2))`