A particle of mass m moves in a circle of radius R in such a way that its speed `(v)` varies with distance (s) as `v = a sqrt(s)` where a is a constant. Calcualte the acceleration and force on the particle.

Options

A. `a^(2)sqrt((1)/(4)-(S^(2))/(R^(2)))`
B. `a^(2)sqrt((1)/(4)+(S^(2))/(R^(2)))`
C. `asqrt((1)/(2)+(S^(2))/(R^(2)))`
D. `a^(2)sqrt((1)/(2)+(S^(2))/(R^(2)))`

Answer

b

Explanation

`a=sqrt(a_(1)^(2)+a_(1)^(2))`
`=sqrt(((dv)/(dt))^(2)+((v^(2))/(R))^(2))`